Integrand size = 24, antiderivative size = 137 \[ \int x (a+b \arctan (c x)) \left (d+e \log \left (1+c^2 x^2\right )\right ) \, dx=-\frac {b (d-e) x}{2 c}+\frac {b e x}{c}+\frac {b (d-e) \arctan (c x)}{2 c^2}-\frac {b e \arctan (c x)}{c^2}+\frac {1}{2} d x^2 (a+b \arctan (c x))-\frac {1}{2} e x^2 (a+b \arctan (c x))-\frac {b e x \log \left (1+c^2 x^2\right )}{2 c}+\frac {e \left (1+c^2 x^2\right ) (a+b \arctan (c x)) \log \left (1+c^2 x^2\right )}{2 c^2} \]
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Time = 0.08 (sec) , antiderivative size = 137, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 7, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.292, Rules used = {2504, 2436, 2332, 5139, 327, 209, 2498} \[ \int x (a+b \arctan (c x)) \left (d+e \log \left (1+c^2 x^2\right )\right ) \, dx=\frac {e \left (c^2 x^2+1\right ) \log \left (c^2 x^2+1\right ) (a+b \arctan (c x))}{2 c^2}+\frac {1}{2} d x^2 (a+b \arctan (c x))-\frac {1}{2} e x^2 (a+b \arctan (c x))+\frac {b (d-e) \arctan (c x)}{2 c^2}-\frac {b e \arctan (c x)}{c^2}-\frac {b e x \log \left (c^2 x^2+1\right )}{2 c}-\frac {b x (d-e)}{2 c}+\frac {b e x}{c} \]
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Rule 209
Rule 327
Rule 2332
Rule 2436
Rule 2498
Rule 2504
Rule 5139
Rubi steps \begin{align*} \text {integral}& = \frac {1}{2} d x^2 (a+b \arctan (c x))-\frac {1}{2} e x^2 (a+b \arctan (c x))+\frac {e \left (1+c^2 x^2\right ) (a+b \arctan (c x)) \log \left (1+c^2 x^2\right )}{2 c^2}-(b c) \int \left (\frac {(d-e) x^2}{2 \left (1+c^2 x^2\right )}+\frac {e \log \left (1+c^2 x^2\right )}{2 c^2}\right ) \, dx \\ & = \frac {1}{2} d x^2 (a+b \arctan (c x))-\frac {1}{2} e x^2 (a+b \arctan (c x))+\frac {e \left (1+c^2 x^2\right ) (a+b \arctan (c x)) \log \left (1+c^2 x^2\right )}{2 c^2}-\frac {1}{2} (b c (d-e)) \int \frac {x^2}{1+c^2 x^2} \, dx-\frac {(b e) \int \log \left (1+c^2 x^2\right ) \, dx}{2 c} \\ & = -\frac {b (d-e) x}{2 c}+\frac {1}{2} d x^2 (a+b \arctan (c x))-\frac {1}{2} e x^2 (a+b \arctan (c x))-\frac {b e x \log \left (1+c^2 x^2\right )}{2 c}+\frac {e \left (1+c^2 x^2\right ) (a+b \arctan (c x)) \log \left (1+c^2 x^2\right )}{2 c^2}+\frac {(b (d-e)) \int \frac {1}{1+c^2 x^2} \, dx}{2 c}+(b c e) \int \frac {x^2}{1+c^2 x^2} \, dx \\ & = -\frac {b (d-e) x}{2 c}+\frac {b e x}{c}+\frac {b (d-e) \arctan (c x)}{2 c^2}+\frac {1}{2} d x^2 (a+b \arctan (c x))-\frac {1}{2} e x^2 (a+b \arctan (c x))-\frac {b e x \log \left (1+c^2 x^2\right )}{2 c}+\frac {e \left (1+c^2 x^2\right ) (a+b \arctan (c x)) \log \left (1+c^2 x^2\right )}{2 c^2}-\frac {(b e) \int \frac {1}{1+c^2 x^2} \, dx}{c} \\ & = -\frac {b (d-e) x}{2 c}+\frac {b e x}{c}+\frac {b (d-e) \arctan (c x)}{2 c^2}-\frac {b e \arctan (c x)}{c^2}+\frac {1}{2} d x^2 (a+b \arctan (c x))-\frac {1}{2} e x^2 (a+b \arctan (c x))-\frac {b e x \log \left (1+c^2 x^2\right )}{2 c}+\frac {e \left (1+c^2 x^2\right ) (a+b \arctan (c x)) \log \left (1+c^2 x^2\right )}{2 c^2} \\ \end{align*}
Time = 0.07 (sec) , antiderivative size = 105, normalized size of antiderivative = 0.77 \[ \int x (a+b \arctan (c x)) \left (d+e \log \left (1+c^2 x^2\right )\right ) \, dx=\frac {c x (-b (d-3 e)+a c (d-e) x)+e \left (a-b c x+a c^2 x^2\right ) \log \left (1+c^2 x^2\right )+b \arctan (c x) \left (d+c^2 d x^2-e \left (3+c^2 x^2\right )+\left (e+c^2 e x^2\right ) \log \left (1+c^2 x^2\right )\right )}{2 c^2} \]
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Time = 1.24 (sec) , antiderivative size = 168, normalized size of antiderivative = 1.23
method | result | size |
parallelrisch | \(\frac {\arctan \left (c x \right ) \ln \left (c^{2} x^{2}+1\right ) b \,c^{2} e \,x^{2}+\arctan \left (c x \right ) b \,c^{2} d \,x^{2}-\arctan \left (c x \right ) b \,c^{2} e \,x^{2}+\ln \left (c^{2} x^{2}+1\right ) a \,c^{2} e \,x^{2}+a \,c^{2} d \,x^{2}-a \,c^{2} e \,x^{2}-\ln \left (c^{2} x^{2}+1\right ) b c e x -b c d x +3 b c e x +\arctan \left (c x \right ) \ln \left (c^{2} x^{2}+1\right ) b e +\arctan \left (c x \right ) b d -3 e b \arctan \left (c x \right )+\ln \left (c^{2} x^{2}+1\right ) a e}{2 c^{2}}\) | \(168\) |
default | \(\text {Expression too large to display}\) | \(2929\) |
parts | \(\text {Expression too large to display}\) | \(2929\) |
risch | \(\text {Expression too large to display}\) | \(21445\) |
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Time = 0.27 (sec) , antiderivative size = 116, normalized size of antiderivative = 0.85 \[ \int x (a+b \arctan (c x)) \left (d+e \log \left (1+c^2 x^2\right )\right ) \, dx=\frac {{\left (a c^{2} d - a c^{2} e\right )} x^{2} - {\left (b c d - 3 \, b c e\right )} x + {\left ({\left (b c^{2} d - b c^{2} e\right )} x^{2} + b d - 3 \, b e\right )} \arctan \left (c x\right ) + {\left (a c^{2} e x^{2} - b c e x + a e + {\left (b c^{2} e x^{2} + b e\right )} \arctan \left (c x\right )\right )} \log \left (c^{2} x^{2} + 1\right )}{2 \, c^{2}} \]
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Time = 0.53 (sec) , antiderivative size = 202, normalized size of antiderivative = 1.47 \[ \int x (a+b \arctan (c x)) \left (d+e \log \left (1+c^2 x^2\right )\right ) \, dx=\begin {cases} \frac {a d x^{2}}{2} + \frac {a e x^{2} \log {\left (c^{2} x^{2} + 1 \right )}}{2} - \frac {a e x^{2}}{2} + \frac {a e \log {\left (c^{2} x^{2} + 1 \right )}}{2 c^{2}} + \frac {b d x^{2} \operatorname {atan}{\left (c x \right )}}{2} + \frac {b e x^{2} \log {\left (c^{2} x^{2} + 1 \right )} \operatorname {atan}{\left (c x \right )}}{2} - \frac {b e x^{2} \operatorname {atan}{\left (c x \right )}}{2} - \frac {b d x}{2 c} - \frac {b e x \log {\left (c^{2} x^{2} + 1 \right )}}{2 c} + \frac {3 b e x}{2 c} + \frac {b d \operatorname {atan}{\left (c x \right )}}{2 c^{2}} + \frac {b e \log {\left (c^{2} x^{2} + 1 \right )} \operatorname {atan}{\left (c x \right )}}{2 c^{2}} - \frac {3 b e \operatorname {atan}{\left (c x \right )}}{2 c^{2}} & \text {for}\: c \neq 0 \\\frac {a d x^{2}}{2} & \text {otherwise} \end {cases} \]
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Time = 0.27 (sec) , antiderivative size = 149, normalized size of antiderivative = 1.09 \[ \int x (a+b \arctan (c x)) \left (d+e \log \left (1+c^2 x^2\right )\right ) \, dx=\frac {1}{2} \, a d x^{2} + \frac {1}{2} \, {\left (x^{2} \arctan \left (c x\right ) - c {\left (\frac {x}{c^{2}} - \frac {\arctan \left (c x\right )}{c^{3}}\right )}\right )} b d - \frac {{\left (x \log \left (c^{2} x^{2} + 1\right ) - 3 \, x + \frac {2 \, \arctan \left (c x\right )}{c}\right )} b e}{2 \, c} - \frac {{\left (c^{2} x^{2} - {\left (c^{2} x^{2} + 1\right )} \log \left (c^{2} x^{2} + 1\right ) + 1\right )} b e \arctan \left (c x\right )}{2 \, c^{2}} - \frac {{\left (c^{2} x^{2} - {\left (c^{2} x^{2} + 1\right )} \log \left (c^{2} x^{2} + 1\right ) + 1\right )} a e}{2 \, c^{2}} \]
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\[ \int x (a+b \arctan (c x)) \left (d+e \log \left (1+c^2 x^2\right )\right ) \, dx=\int { {\left (b \arctan \left (c x\right ) + a\right )} {\left (e \log \left (c^{2} x^{2} + 1\right ) + d\right )} x \,d x } \]
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Time = 1.42 (sec) , antiderivative size = 227, normalized size of antiderivative = 1.66 \[ \int x (a+b \arctan (c x)) \left (d+e \log \left (1+c^2 x^2\right )\right ) \, dx=\frac {a\,d\,x^2}{2}-\frac {a\,e\,x^2}{2}-\frac {b\,d\,x}{2\,c}+\frac {3\,b\,e\,x}{2\,c}+\frac {b\,d\,x^2\,\mathrm {atan}\left (c\,x\right )}{2}-\frac {b\,e\,x^2\,\mathrm {atan}\left (c\,x\right )}{2}+\frac {a\,e\,\ln \left (c^2\,x^2+1\right )}{2\,c^2}+\frac {b\,d\,\mathrm {atan}\left (\frac {b\,c\,d\,x}{b\,d-3\,b\,e}-\frac {3\,b\,c\,e\,x}{b\,d-3\,b\,e}\right )}{2\,c^2}-\frac {3\,b\,e\,\mathrm {atan}\left (\frac {b\,c\,d\,x}{b\,d-3\,b\,e}-\frac {3\,b\,c\,e\,x}{b\,d-3\,b\,e}\right )}{2\,c^2}+\frac {a\,e\,x^2\,\ln \left (c^2\,x^2+1\right )}{2}-\frac {b\,e\,x\,\ln \left (c^2\,x^2+1\right )}{2\,c}+\frac {b\,e\,\mathrm {atan}\left (c\,x\right )\,\ln \left (c^2\,x^2+1\right )}{2\,c^2}+\frac {b\,e\,x^2\,\mathrm {atan}\left (c\,x\right )\,\ln \left (c^2\,x^2+1\right )}{2} \]
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